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Posted by: Bankroll at January 27, 2004, 5:42 pm

Topic: Playing suited/straight suited pocket cards Forum: Bonus Whores

This may still not mean anything to you, but here goes:

First Equation is ((11 CHOOSE 2) * (39 CHOOSE 1)) / (50 CHOOSE 3)

where (X CHOOSE Y) = X! / ((X-Y)! * Y!)

where Z! = Z * (Z-1) * (Z-2)... * 1 so 5! = 5 * 4 * 3 * 2 * 1

* = multiplication
/ = division

11 = # of the suit remaining in the deck of which you're choosing exactly 2 to be on the flop
39 = remaining cards in the deck that are not of that suit of which you're choosing 1
50 = total number of cards excluding the two in your hand from which to choose a 3 card flop

so the numerator counts the number of ways that you can flop exactly two of your designated suit, that is you choose two of your suit from the 11 remaining and 1 card from the remaining 39 cards

and the denominator is the total number of ways the flop can come from the remaining 50 cards unseen by you

the quotient is that percentage of all possible flops that contain exactly 2 of your suit

The other computation is done in a similar manner.

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